A fictitious example

We have seen: as long as the function name and the parameter list and the return type for a function is unique, the C++ compiler can distinguish between the functions.

class example {

public:

virtual void function (const int);

virtual void function (const int, const float);

virtual void function (const int, const *float);

virtual void function (const int, const double);

virtual void function (const int, const *double);

virtual void function (const float);

virtual void function (const float, const float);

virtual void function (const float, const *float);

virtual void function (const float, const double);

virtual void function (const float, const *double);

virtual int function (const int);

virtual int function (const int, const float);

virtual int function (const int, const *float);

virtual int function (const int, const double);

virtual int function (const int, const *double);

virtual int function (const float);

virtual int function (const float, const float);

virtual int function (const float, const *float);

virtual int function (const float, const double);

virtual int function (const float, const *double);

};

All the declarations on the left are ok -- all the “function” routines can be distinguished by their parameter list and return type.

example *e = new example();

int i = 0;

int j;

float x = 3.1415;

double d = 3.141592654;

e->function(i);

e->function(i,x);

e->function(i,d);

j = e->function(i);

j = e->function(i,x);

j = e->function(i,d);

j = e->function(x,&d);

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